MATH SOLVE

4 months ago

Q:
# Item 1 A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. a. How many possible outcomes are there?

Accepted Solution

A:

Answer:4 possible outcomesStep-by-step explanation:we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space. The size of the sample space is the total number of possible outcomes The event space is the number of outcomes in the event you are interested in. so Let
x------> size of the event space
y-----> size of the sample space so
[tex]P=\frac{x}{y}[/tex] In this problemThe probability of choose a blue card is
[tex]x=7[/tex]
[tex]y=7+4+6+8=25[/tex]
substitute
[tex]P=\frac{7}{25}[/tex]
The probability of choose a green card is
[tex]x=4[/tex]
[tex]y=7+4+6+8=25[/tex]
substitute
[tex]P=\frac{4}{25}[/tex]
The probability of choose a red card is
[tex]x=6[/tex]
[tex]y=7+4+6+8=25[/tex]
substitute
[tex]P=\frac{6}{25}[/tex]
The probability of choose a yellow card is
[tex]x=8[/tex]
[tex]y=7+4+6+8=25[/tex]
substitute
[tex]P=\frac{8}{25}[/tex]
The sum of the probabilities of the 4 possible outcomes is equal to[tex]\frac{7}{25}+\frac{4}{25}+\frac{6}{25}+\frac{8}{25}=\frac{25}{25}[/tex] ----> represent the 100%