A car drove 330 miles in 6 hours at a constant rate. If the car’s rate of travel slows by 10 mph, what is the new, slower rate of travel?

Answer:45 mphStep-by-step explanation:Given: Distance travelled= 330 miles            Time taken= 6 h Lets find out speed of car drove.Formula; [tex]Speed= \frac{Distance}{time}[/tex]Speed= [tex]\frac{330}{6} = 55\ mph[/tex]∴ Car´s speed is 55 mph.As we have been informed that car´s rate of travel slows by 10 mph∴ we have to reduce the current speed of car by 10 mph; [tex](55-10)= 45\ mph[/tex]The new slower rate of travel is 45 mph.